# Practice Demo

**Find the following limit:**

$$\lim_{x\to-3^+} \frac{3+x}{|3+x|}$$

Preview your answer:

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**Hint 1:** For the function $_\frac{3+x}{|3+x|}_$, we are interested in what happens as $_x_$ approaches $_-3_$ from the right side.

**Hint 2:** The function $_\frac{3+x}{|3+x|}_$ has a discontinuity at $_x=-3_$.

**Hint 3:** Since the function is not continuous at $_x=-3_$, we cannot use the value of $_f(x)_$ at $_x=-3_$. Instead, we must find the value $_\frac{3+x}{|3+x|}_$ approaches as $_x_$ approaches $_-3_$ from the right side.

**Solution:**

The function $_\frac{3+x}{|3+x|}_$ approaches $_1_$ as $_x_$ approaches $_-3_$ from the right side.

Therefore:

$$\lim_{x\to-3^+} \frac{3+x}{|3+x|} = \color{blue}{1}$$